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A Function Containing Its Own Integral

Difficulty: Medium · Topics: Calculus, Integration, Functional Equations

O‘z integralini o‘z ichiga olgan funksiya

f(x)=x√2x-x^2-∫ 0^1f(x) dx

Find ∫ 0^1f(x) dx.

f(x)=x√2x-x^2-∫ 0^1f(x) dx

∫ 0^1f(x) dx ni toping.