A Function Containing Its Own Integral
Difficulty: Medium · Topics: Calculus, Integration, Functional Equations
O‘z integralini o‘z ichiga olgan funksiya
f(x)=x√2x-x^2-∫ 0^1f(x) dx
Find ∫ 0^1f(x) dx.
f(x)=x√2x-x^2-∫ 0^1f(x) dx
∫ 0^1f(x) dx ni toping.