Smallest Sum That Keeps It One-to-One
Difficulty: Hard · Topics: Algebra, Functions, Inverse Functions
Inyektivlikni saqlaydigan eng kichik yig‘indi
a and b are integers and
f(x)=begincasesa(x-2)^2+b, & x<2\\[2pt] -2x+7, & x≥2endcases
is one-to-one on mathbbR. Find the smallest possible value of a+b.
a va b butun sonlar va
f(x)=begincasesa(x-2)^2+b, & x<2\\[2pt] -2x+7, & x≥2endcases
funksiya mathbbR da inyektiv. a+b ning eng kichik mumkin bo‘lgan qiymatini toping.