Odd and Periodic
Difficulty: Hard · Topics: Algebra, Functions, Properties of Functions
Toq va davriy
f:mathbbR→mathbbR is odd, f(x+4)=f(x) for all x, and f(1)=3.
Find f(2025)+f(2026)+f(2027).
f:mathbbR→mathbbR toq, barcha x uchun f(x+4)=f(x), va f(1)=3.
f(2025)+f(2026)+f(2027) ni toping.