Gluing Two Pieces into a Bijection
Difficulty: Hard · Topics: Algebra, Functions, Properties of Functions
Ikki bo‘lakni biyeksiyaga ulash
f(x)=begincases3x+a, & x<2\\[2pt] x^2+2, & x≥ 2endcases
is a bijection from mathbbR onto mathbbR. Find a+f^-1(11).
f(x)=begincases3x+a, & x<2\\[2pt] x^2+2, & x≥ 2endcases
funksiya mathbbR ni mathbbR ga biyektiv akslantiradi. a+f^-1(11) ni toping.