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Differentiating an Integral with Variable Limit

Difficulty: Easy · Topics: Calculus, Fundamental Theorem of Calculus

Yuqori chegarasi o‘zgaruvchi integralni differensiallash

G(x)=∫ 1^x^2e^-t^2 dt.

Find G'(1).

G(x)=∫ 1^x^2e^-t^2 dt.

G'(1) ni toping.