Making a Log Ratio Continuous
Difficulty: Easy · Topics: Calculus, Continuity, Logarithms
Logarifmik nisbatni uzluksiz qilish
If the function defined on ≤ft(-1/3,1/3 ) is continuous,
f(x)=begincases 1/xln≤ft((1+3x)/(1-2x) ), & x≠ 0 \\[8pt] a, & x=0 endcases
then find a.
Agar ≤ft(-1/3,1/3 ) oraliqda aniqlangan
f(x)=begincases 1/xln≤ft((1+3x)/(1-2x) ), & x≠ 0 \\[8pt] a, & x=0 endcases
funksiya uzluksiz bo‘lsa, a ni toping.